700=-5t^2+120t+0

Solution for 700=-5t^2+120t+0 equation:

700=-5t^2+120t+0

We move all terms to the left:

700-(-5t^2+120t+0)=0

We get rid of parentheses

5t^2-120t-0+700=0

We add all the numbers together, and all the variables

5t^2-120t+700=0

a = 5; b = -120; c = +700;
Δ = b2-4ac
Δ = -1202-4·5·700
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-20}{2*5}=\frac{100}{10}
=10
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+20}{2*5}=\frac{140}{10}
=14
$